Respuesta :
Answer:
The system [tex]x+y=7\\3x+2y=17[/tex] has a unique solution [tex]x=3\\y=4[/tex]
Step-by-step explanation:
We have the system of equations:
[tex]x+y=7\\3x+2y=17[/tex]
To solve this system for Gauss-Jordan method we need the augmented matrix, which is:
[tex]\left[\begin{array}{cc|c}1&1&7\\3&2&17\end{array}\right][/tex]
Next we need to transform the augmented matrix to the reduced row echelon form via elementary row operations as follows:
- Row Operation 1: add -3 times the 1st row to the 2nd row
[tex]\left[\begin{array}{cc|c}1&1&7\\0&-1&-4\end{array}\right][/tex]
- Row Operation 2: multiply the 2nd row by -1
[tex]\left[\begin{array}{cc|c}1&1&7\\0&1&4\end{array}\right][/tex]
- Row Operation 3: add -1 times the 2nd row to the 1st row
[tex]\left[\begin{array}{cc|c}1&0&3\\0&1&4\end{array}\right][/tex]
From the reduced row echelon form we have the solution of the system
[tex]x=3\\y=4[/tex]