We know that AD is the shortest way but ABCD is connected in series Equivalent Resistance =R1+R2+R3 =(10+10+10)ohm =30ohm Since BC and AD is connected in parallel 1/Req=1/R1 + 1/R2 =1/30 + 1/10 =3+1/30 =4/30 So, Req=30/4 ohm
Now,Current drawn from the battery => I = V/R => I = 30/4 ohm/3v => I = 30/4*3 So, I = 10/4 A
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