Rewriting the equation in the form y=mx+c -x+3y=9 3y=x+9 y=[tex] \frac{1}{3} x+3[/tex] Gradient is 1/3 Since parallel lines have similar gradients, [tex] \frac{y--3}{x--3}= \frac{1}{3} [/tex] y+3=[tex] \frac{1}{3} (x+3)[/tex] y+3=[tex] \frac{1x}{3} +1[/tex] y=[tex] \frac{1x}{3} -2[/tex]
