Given:
[tex]y=-5(x-5)+1[/tex]
First, let us find two points from this equation.
We can set values of x and then solve for y.
Let us find the values of y when x = 1, 2, 3, 4, 5
[tex]\begin{gathered} y=-5(x-5)+1 \\ y=-5(1-5)+1=21 \\ y=-5(2-5)+1=16 \\ y=-5(3-5)+1=11 \\ y=-5(4-5)+1=6 \\ y=-5(5-5)+1=1 \end{gathered}[/tex]
We now have a set of points:
(1, 21)
(2, 16)
(3, 11)
(4, 6)
(5, 1)
Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)
The graph would then look like this:
