SaxtonC165005 SaxtonC165005
  • 03-11-2022
  • Mathematics
contestada

Could you help walk me through this problem? I keep getting the problem wrong and I don't know why.

Could you help walk me through this problem I keep getting the problem wrong and I dont know why class=

Respuesta :

RhamirD341201 RhamirD341201
  • 03-11-2022

to solve this we can get the equation in the form

F(x)=a(x-X1)(x-X2)

where X1 and X2 are the values of X where the line cross the axial X

in this case

X1= -1

X2= 2

so the function will be

F(x)=a*(x+1)*(x-2)

now we need to find the value of a

So for this we can replace with a random point of the curve, for example the point x= 0 y=-2

So if we replace

-2=a*(0+1)*(0-2)

-2=a*1*-2

-2=a*-2

-2/-2=a=1

So the answer is:

F(x)=1*(x+1)*(x-2)

Answer Link

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