Log (C+3) base 3 - log (4C-1) base 3 = log 5 base 3

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03-03-2017
Mathematics

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Log (C+3) base 3 - log (4C-1) base 3 = log 5 base 3

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jdoe0001 jdoe0001 · Answer 1 · 2017-03-03T23:46:17+01:00

jdoe0001 jdoe0001

03-03-2017

[tex]\bf log_3(c+3)-log_3(4c-1)=log_3(5)\\\\ -----------------------------\\\\ log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\qquad thus\\\\ -----------------------------\\\\ log_3\left( \frac{c+3}{4c-1} \right)=log_3(5)\implies \cfrac{c+3}{4c-1}=5[/tex]

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