tracionShjobriaral tracionShjobriaral
  • 01-04-2017
  • Mathematics
contestada

According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x23 + 41x19 + 13x5− 10 have?
3
5
19
23

Respuesta :

wolf1728
wolf1728 wolf1728
  • 01-04-2017
The solutions to an algebraic equation equal the highest power in that equation.  So, in this case, the answer is 23.


Answer Link
InesWalston
InesWalston InesWalston
  • 27-11-2018

Answer:

The function has 23 zeros.

Step-by-step explanation:

Fundamental Theorem of Algebra-

Any polynomial of degree n has n roots or zeros.

The given function is,

[tex]f(x) = 15x^{23} + 41x^{19} + 13x^5- 10[/tex]

In the polynomial [tex]15x^{23} + 41x^{19} + 13x^5- 10[/tex], the highest power is 23.

So, according to fundamental theorem of algebra, there must be 23 roots or zeros of this polynomial.

Answer Link

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