04-04-2017
Chemistry

contestada

How many grams of Lead(II) nitrate are present in 150.0 mL of an Lead(II) nitrate solution that is 0.07268 M?

Respuesta :

AnonymousA7 AnonymousA7

04-04-2017

hey...
Use the molarity formula
M=moles/L and then convert to grams

0.07268*0.15=moles
0.010902 mol
Pb(NO3)2
1 mole=331.22g
0.010902 moles=

3.61 g

Answer Link

Otras preguntas

Explain which drawing medium would work best for this artwork and why.

y + X ZX x². x+y X- -) 2)*( x+y y². X²

Determine the interval(s) for which the function shown below is increasing. Write your response in interval notation using the symbol ∪ when necessary.

3z +9y = 7 3z +9y=10

A bowl contains & green grapes, 10 red grapes and 8 black gomps 1 following of probality of Choosing which of the a red grupe 6x-15 = 6 and then without put

this is due today pls help pls

The following are the steps of performing chest compressions on a child.

What is m∠2 if m∠1 is 46 degrees

How did the war challenge the colonies economically?

The following are the steps of performing chest compressions on a child.