Answer: P(S\cup T)=72%
Step-by-step explanation:
We are given that S and T are mutually exclusive events.
Therefore, the intersection of both the events must be 0.
i.e. [tex]p(S\cap T)=0[/tex]
P (S) = 65% and P(T) = 7%
We know that P(S or T)=[tex]P(S\cup T)=P(S)+P(T)-P(S\cap T)[/tex]
[tex]\Rightarrow P(S\cup T)=65\%+7\%=72\%[/tex]
Hence, P(S\cup T)=72%
