kylamchavez
kylamchavez kylamchavez
  • 03-03-2018
  • Mathematics
contestada

find the roots of the polynomial equation x^3-x^2+x+39=0

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zhaotianyu369 zhaotianyu369
  • 03-03-2018
According to the rational root theorem, since the leading coefficient of the polynomial is 1, the real answer is a factor of 39. Try a few possible values, and we find that x=-3 works. Divide x+3 from (x^3-x^2+x+39), we have (x^2-4x+13). x^2-4x+13=0,
x^2-4x+4=-9,
(x-2)^2=-9
x-2=+-3i,
x=2+3i or 2-3i.
The roots are -3, 2+3i, 2-3i.
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emilybrown0812
emilybrown0812 emilybrown0812
  • 07-12-2020

Answer:

B

Step-by-step explanation:

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