tspurg6279 tspurg6279
  • 01-04-2018
  • Mathematics
contestada

Write an equation of the line that is perpendicular to y = 1 2 x + 3 and passes through the point (10, -5).

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von89
von89 von89
  • 01-04-2018
y=mx+c

1) FIND M

Perpendicular lines formula
m1 x m2 = -1
- gradient of the lines multiplied together equals to -1

Substitute
m1 x m2 = -1
12 x m2 = -1
m2 = -1/12
m2 = -0.083

2) FIND C
Now we know m, y and x, so we can find c.
(x,y) -> (10,-5)

y=mx+c
-5=-0.083*10+c
-5=0.83+c
-5-0.83=c
c=-5.83

So the equation would be
y=-0.08x+5.83
Answer Link
kthegoat20
kthegoat20 kthegoat20
  • 13-01-2020

Answer:

A) y = -2x + 15

Step-by-step explanation:

Answer Link

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