jailynj4820 jailynj4820
  • 02-04-2018
  • Chemistry
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What is the temperature of a 1.59 L flask containing 0.175 mol of Ne at a pressure of 1.09 atm?

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blahblahmali blahblahmali
  • 11-04-2018
We can use the ideal gas law equation;
PV = nRT
P - pressure, V - volume , R - universal gas constant, n - number of moles and T - temperature 
P - 1 atm - 101 325 Pa
   1.09 atm - 1.09 atm x 101 325 Pa/atm = 110 444 Pa
n - 0.175 mol 
V - 1.59 x 10⁻³ m³
substituting the values in the equation 
110 444 Pa x 1.59 x 10⁻³ m³ = 0.175 mol x 8.314 Jmol⁻¹K⁻¹ x T
T = 120.70 K


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