Given that on the graph of y=f(x) the slope at any point (x,y) is always twice the value of x, and f(2)=3, the the function will be given by: y=kx where k is the slope. but y=3 when x=2 hence plugging in the above and solving for k we obtain: 3=2k hence k=3/2 thus y=3/2x thus f(3) will be evaluated as follows: x=3 plugging in the formula we get: y=f(3)=3/2(3)=9/2=4.5
